3.2.67 \(\int \frac {(c x)^m}{(b x^n)^{5/2}} \, dx\) [167]

Optimal. Leaf size=36 \[ \frac {2 x^{1-2 n} (c x)^m}{b^2 (2+2 m-5 n) \sqrt {b x^n}} \]

[Out]

2*x^(1-2*n)*(c*x)^m/b^2/(2+2*m-5*n)/(b*x^n)^(1/2)

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Rubi [A]
time = 0.01, antiderivative size = 36, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 3, integrand size = 15, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.200, Rules used = {15, 20, 30} \begin {gather*} \frac {2 x^{1-2 n} (c x)^m}{b^2 (2 m-5 n+2) \sqrt {b x^n}} \end {gather*}

Antiderivative was successfully verified.

[In]

Int[(c*x)^m/(b*x^n)^(5/2),x]

[Out]

(2*x^(1 - 2*n)*(c*x)^m)/(b^2*(2 + 2*m - 5*n)*Sqrt[b*x^n])

Rule 15

Int[(u_.)*((a_.)*(x_)^(n_))^(m_), x_Symbol] :> Dist[a^IntPart[m]*((a*x^n)^FracPart[m]/x^(n*FracPart[m])), Int[
u*x^(m*n), x], x] /; FreeQ[{a, m, n}, x] &&  !IntegerQ[m]

Rule 20

Int[(u_.)*((a_.)*(v_))^(m_)*((b_.)*(v_))^(n_), x_Symbol] :> Dist[b^IntPart[n]*((b*v)^FracPart[n]/(a^IntPart[n]
*(a*v)^FracPart[n])), Int[u*(a*v)^(m + n), x], x] /; FreeQ[{a, b, m, n}, x] &&  !IntegerQ[m] &&  !IntegerQ[n]
&&  !IntegerQ[m + n]

Rule 30

Int[(x_)^(m_.), x_Symbol] :> Simp[x^(m + 1)/(m + 1), x] /; FreeQ[m, x] && NeQ[m, -1]

Rubi steps

\begin {align*} \int \frac {(c x)^m}{\left (b x^n\right )^{5/2}} \, dx &=\frac {x^{n/2} \int x^{-5 n/2} (c x)^m \, dx}{b^2 \sqrt {b x^n}}\\ &=\frac {\left (x^{-m+\frac {n}{2}} (c x)^m\right ) \int x^{m-\frac {5 n}{2}} \, dx}{b^2 \sqrt {b x^n}}\\ &=\frac {2 x^{1-2 n} (c x)^m}{b^2 (2+2 m-5 n) \sqrt {b x^n}}\\ \end {align*}

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Mathematica [A]
time = 0.01, size = 26, normalized size = 0.72 \begin {gather*} \frac {x (c x)^m}{\left (1+m-\frac {5 n}{2}\right ) \left (b x^n\right )^{5/2}} \end {gather*}

Antiderivative was successfully verified.

[In]

Integrate[(c*x)^m/(b*x^n)^(5/2),x]

[Out]

(x*(c*x)^m)/((1 + m - (5*n)/2)*(b*x^n)^(5/2))

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Maple [A]
time = 0.03, size = 26, normalized size = 0.72

method	result	size
gosper	\(\frac {2 x \left (c x \right )^{m}}{\left (2+2 m -5 n \right ) \left (b \,x^{n}\right )^{\frac {5}{2}}}\)	\(26\)

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((c*x)^m/(b*x^n)^(5/2),x,method=_RETURNVERBOSE)

[Out]

2*x/(2+2*m-5*n)*(c*x)^m/(b*x^n)^(5/2)

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Maxima [A]
time = 0.31, size = 27, normalized size = 0.75 \begin {gather*} \frac {2 \, c^{m} x x^{m}}{b^{\frac {5}{2}} {\left (2 \, m - 5 \, n + 2\right )} {\left (x^{n}\right )}^{\frac {5}{2}}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((c*x)^m/(b*x^n)^(5/2),x, algorithm="maxima")

[Out]

2*c^m*x*x^m/(b^(5/2)*(2*m - 5*n + 2)*(x^n)^(5/2))

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Fricas [F(-2)]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Exception raised: TypeError} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((c*x)^m/(b*x^n)^(5/2),x, algorithm="fricas")

[Out]

Exception raised: TypeError >>  Error detected within library code:   integrate: implementation incomplete (ha
s polynomial part)

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Sympy [F(-2)]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Exception raised: SystemError} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((c*x)**m/(b*x**n)**(5/2),x)

[Out]

Exception raised: SystemError >> excessive stack use: stack is 3005 deep

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Giac [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((c*x)^m/(b*x^n)^(5/2),x, algorithm="giac")

[Out]

integrate((c*x)^m/(b*x^n)^(5/2), x)

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Mupad [B]
time = 1.05, size = 34, normalized size = 0.94 \begin {gather*} \frac {2\,x^{1-3\,n}\,\sqrt {b\,x^n}\,{\left (c\,x\right )}^m}{b^3\,\left (2\,m-5\,n+2\right )} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((c*x)^m/(b*x^n)^(5/2),x)

[Out]

(2*x^(1 - 3*n)*(b*x^n)^(1/2)*(c*x)^m)/(b^3*(2*m - 5*n + 2))

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